MULTIPLE CHOICE
13.47 The critical path of a network is the
(a) shortest time path through the network.
(b) path with the fewest activities.
(c) path with the most activities.
(d) longest time path through the network.
(e) none of the above
13.48 In a PERT network, the earliest (activity) start time is the
(a) earliest time that an activity can be finished without delaying the entire project.
(b) latest time that an activity can be started without delaying the entire project.
(c) earliest time that an activity can start without violation of precedence requirements.
(d) latest time that an activity can be finished without delaying the entire project.
(e) none of the above
13.49 Slack time in a network is the
(a) time consuming job or task that is a key subpart of the total project.
(b) shortest amount of time that could be required to complete the activity.
(c) amount of time that you would expect it would take to complete the activity.
(d) amount of time that an activity can be delayed without delaying the entire project.
(e) none of the above
13.50 A network activity is a
(a) point in time that marks the beginning or ending of an activity.
(b) time consuming job that is a subpart of the total project.
(c) graphical display of a project.
(d) network technique that allows three time estimates for each activity in a project.
(e) the longest time path through the network.
13.51 Which of the following is not a concept associated with CPM?
(a) normal time
(b) probability
(c) normal cost
(d) crash cost
(e) deterministic network
13.52 PERT
(a) assumes we do not know ahead of time what activities must be completed.
(b) allows computation of the program’s evaluation.
(c) is a network technique that uses three time estimates for each activity in a project.
(d) is a deterministic network technique that allows for project crashing.
(e) none of the above
13.53 CPM
(a) assumes we do not know ahead of time what activities must be completed.
(b) is opposite to that of PERT, as it does not consider the network activities.
(c) is a network technique that allows three time estimates for each activity in a project.
(d) is a deterministic network technique that allows for project crashing.
(e) none of the above
13.54 Managers use the network analysis of PERT and CPM to help them
(a) derive flexibility by identifying noncritical activities.
(b) replan, reschedule, and reallocate resources such as manpower and finances.
(c) plan, schedule, monitor, and control large and complex projects.
(d) all of the above
13.55 In contrast to PERT or PERT/cost, CPM
(a) is a deterministic network model.
(b) uses crash times and costs.
(c) allows for calculating the least additional cost for shortening the project time.
(d) assumes that the activity times and costs are known with certainty.
(e) all of the above
13.56 The expected time in PERT is
(a) a weighted average of the most optimistic time, most pessimistic time, and four times the most likely time.
(b) the modal time of a beta distribution.
(c) a simple average of the most optimistic, most likely, and most pessimistic times.
(d) the square root of the sum of the variances of the activities on the critical path.
(e) none of the above
13.57 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 4, 5, and 12 days, respectively, compute the PERT time for this activity.
(a) 5
(b) 6
(c) 7
(d) 12
(e) none of the above
13.58 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 3, 3, and 9 days, respectively, compute the PERT time for this activity.
(a) 3
(b) 4
(c) 5
(d) 9
(e) none of the above
13.59 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 4, 8, and 18 days, respectively, compute the PERT time for this activity.
(a) 4
(b) 8
(c) 9
(d) 18
(e) none of the above
13.60 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 2, 10, and 20 days, respectively, compute the PERT variance for this activity.
(a) 3
(b) 6
(c) 9
(d) 18
(e) none of the above
13.61 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 4, 12, and 18 days, respectively, compute the PERT variance for this activity.
(a) 2.33
(b) 5.44
(c) 8.00
(d) 64.00
(e) none of the above
13.62 Given an activity’s optimistic, most likely and pessimistic time estimates of 3, 5, and 15 days, respectively, compute the PERT standard deviation for this activity.
(a) 2
(b) 4
(c) 5
(d) 15
(e) none of the above
13.63 Given the following small project, the critical path is _______ days.
Activity Immediate
Predecessor Time
(days)
A – 10
B – 4
C A, B 6
(a) 10
(b) 14
(c) 16
(d) 20
(e) none of the above
13.64 Given the following small project, the critical path is _______ days.
Activity Immediate
Predecessor Time
(days)
A – 8
B A 4
C – 10
(a) 4
(b) 10
(c) 12
(d) 22
(e) none of the above
The following table provides information for questions 13.65 to 13.68.
Table 13-1
The following represents a project with known activity times. All times are in weeks.
Activity Immediate
Predecessor Time
A – 4
B – 3
C A 2
D B 7
E C, D 4
F B 5
13.65 Using the data in Table 13-1, what is the minimum possible time required for completing the project?
(a) 8
(b) 14
(c) 25
(d) 10
(e) none of the above
13.66 Using the data in Table 13-1, what is the latest possible time that C may be started without delaying completion of the project?
(a) 0
(b) 4
(c) 8
(d) 10
(e) none of the above
13.67 According to Table 13-1, compute the slack time for activity D.
(a) 0
(b) 5
(c) 3
(d) 6
(e) none of the above
13.68 Using the data in Table 13-1, compute the latest finish time for activity E.
(a) 4
(b) 10
(c) 14
(d) 25
(e) none of the above
The following table provides information for questions 13.69 to 13.72.
Table 13-2
The following represents a project with four activities. All times are in weeks.
Activity Immediate
Predecessor Optimistic
Time Most
Likely
Time Pessimistic
Time
A – 2 8 14
B – 8 8 8
C A 6 9 18
D B 5 11 17
13.69 According to the data in Table 13-2, what is the critical path?
(a) A, B
(b) A, C
(c) B, D
(d) A, B, C, D
(e) none of the above
13.70 According to the data in Table 13-2, what is the minimum expected completion time for the project?
(a) 18
(b) 19
(c) 37
(d) 11
(e) none of the above
13.71 According to Table 13-2, there are four activities in the project. Assume the normal distribution is appropriate to use to determine the probability of finishing by a particular time. If you wished to find the probability of finishing the project in 20 weeks or less, it would be necessary to find the variance and then the standard deviation to be used with the normal distribution. What variance would be used?
(a) 2
(b) 4
(c) 8
(d) 12
(e) none of the above
13.72 According to Table 13-2, there are four activities in the project. Assume the normal distribution is appropriate to use to determine the probability of finishing by a particular time. What is the probability that the project is finished in 16 weeks or less (round to two decimals)?
(a) 0.07
(b) 0.93
(c) 0.43
(d) 0.77
(e) none of the above
13.73 Consider a project that has an expected completion time of 60 weeks and a standard deviation of five weeks. What is the probability that the project is finished in 70 weeks or less (round to two decimals)?
(a) 0.98
(b) 0.48
(c) 0.50
(d) 0.02
(e) none of the above
13.74 Your company is considering submitting a bid on a major project. You determine that the expected completion time is 100 weeks and the standard deviation is 10 weeks. It is assumed that the normal distribution applies. You wish to set the due date for the project such that there is an 85 percent chance that the project will be finished by this time. What due date should be set?
(a) 108.0
(b) 110.4
(c) 89.6
(d) 85.0
(e) none of the above
The following table provides information for questions 13.75 to 13.76.
Table 13-3
Activity Immediate
Predecessor Time
ES EF LS LF
A – 4 0 4 6 10
B – 5 0 5 0 5
C A 3 4 7 10 13
D B 8 5 13 5 13
E B 3 5 8 14 17
F C, D 2 13 15 15 17
G C, D 6 13 19 13 19
H E, F 2 15 17 17 19
13.75 According to Table 13-3, there are eight activities to be completed in a project with known activity times. How long could activity E be delayed without delaying the completion of the project?
(a) 3
(b) 9
(c) 14
(d) 17
(e) none of the above
13.76 According to Table 13-3, there are eight activities to be completed in a project with known activity times. What is the minimum possible time required for completing the project?
(a) 13
(b) 15
(c) 17
(d) 19
(e) 33
The following table provides information for questions 13.77 to 13.79.
Table 13-4
Activity Immediate
Predecessor Optimistic
Most
Likely Pessimistic Average Standard
Deviation Variance
A – 4 5 6 5 0.333 0.111
B – 2 5 8 5 1.000 1.000
C A 2 8 14 8 2.000 4.000
D A 5 5 5 5 0.000 0.000
E B, C 6 7 8 7 0.333 0.111
13.77 According to Table 13-4, there are five activities in a PERT project. Which activities are on the critical path?
(a) A,B,C,D,E
(b) A,C,E
(c) B,D
(d) A,B,C,D
(e) none of the above
13.78 According to Table 13-4, there are five activities in a PERT project. What is the variance of the critical path?
(a) 5.222
(b) 4.222
(c) 1.222
(d) 0
(e) none of the above
13.79 According to Table 13-4, there are five activities in a PERT project. If the normal distribution were used to find the probability of finishing this project in 24 weeks or less, what mean and variance would be used?
(a) 20 and 4.222
(b) 30 and 5.222
(c) 20 and 5.222
(d) 30 and 4.222
(e) none of the above
13.80 The critical path of a network is the
(a) path with the least variance.
(b) path with zero slack.
(c) path with the most activities.
(d) path with the largest variance.
(e) none of the above
13.81 In a PERT network, the latest (activity) start time is the
(a) earliest time that an activity can be finished without delaying the entire project.
(b) latest time that an activity can be started without delaying the entire project.
(c) earliest time that an activity can start without violation of precedence requirements.
(d) latest time that an activity can be finished without delaying the entire project.
(e) none of the above
13.82 Slack time in a network is the
(a) time consuming job or task that is a key subpart of the total project.
(b) shortest amount of time that could be required to complete the activity.
(c) amount of time that you would expect it would take to complete the activity.
(d) amount of time that an activity can be delayed without delaying the project.
(e) none of the above
13.83 To do a PERT analysis of a project,
(a) we must know the sequence in which tasks are to be performed.
(b) we must know the number of tasks in the project.
(c) we must know the time estimates for each activity.
(d) we must compute an expected time for each activity.
(e) all of the above
13.84 For which of the following projects are we more likely to use PERT than CPM as a management tool?
(a) performing maintenance in a chemical plant
(b) building a new hotel complex
(c) developing a new space vehicle
(d) constructing a new factory
(e) building a new highway
13.85 PERT
(a) assumes we do not know ahead of time the specific amount of time an activity will require.
(b) allows time/cost trade-offs.
(c) is a probabilistic network technique that allows for project crashing.
(d) is a deterministic network technique that allows for project crashing.
(e) none of the above
13.86 In PERT,
(a) an activity may not start until all activities scheduled for an earlier time have finished.
(b) we can have no more than two activities taking place simultaneously.
(c) after the project has begun, it is possible for a path other than the original critical path to become critical.
(d) we assume that the time to complete an activity is described by the normal distribution.
(e) none of the above
13.87 Which of the following is incorrect? In PERT,
(a) we assume that all activities are completed.
(b) an activity may not start until all activities scheduled for an earlier time have finished.
(c) we assume that all activities have definable start and end points.
(d) we assume that the time to complete an activity is described by the beta distribution.
(e) none of the above
13.88 In PERT, we assume that
(a) the times to complete individual activities are known with certainty.
(b) all activities are carried out by staff from our own organization.
(c) the total cost of a project is independent of the time to complete the project.
(d) the total time to complete all activities on the critical path is described by a normal distribution.
(e) none of the above
13.89 CPM
(a) assumes that we know ahead of time all activities which must be completed.
(b) assumes that we may obtain additional resources or move existing resources from one activity to another.
(c) is an important technique when we are planning a project similar to projects we have completed in the past.
(d) is a deterministic network technique that allows for time/cost trade-offs.
(e) all of the above
13.90 In CPM,
(a) an activity may start before its immediate predecessors have finished.
(b) no more than two activities may be performed simultaneously.
(c) the total cost of completing an activity in the crash time is higher than the normal cost.
(d) when we crash an activity, we complete the activity in the minimum possible time.
(e) none of the above
13.91 Managers use the network analysis of PERT and CPM to help them
(a) identify the need for contingency plans by identifying critical activities.
(b) learn more about the actual times required to complete the activities.
(c) understand the relationship between the various activities.
(d) all of the above
(e) (a) & (c) only
13.92 In contrast to CPM, PERT
(a) is a deterministic network model.
(b) requires all activities to be completed.
(c) assumes that activity costs are unknown.
(d) can identify activities which may, but do not necessarily, lie on the critical path.
(e) all of the above
13.93 The expected time in PERT is
(a) greater than the most likely time.
(b) equal to the most likely time.
(c) less than the most likely time.
(d) could be any of the above.
(e) none of the above
13.94 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 3, 7, and 11 days, respectively, compute the expected time for this activity.
(a) 5
(b) 6
(c) 7
(d) 12
(e) none of the above
13.95 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 3, 5, and 13 days, respectively, compute the expected time for this activity.
(a) 3
(b) 4
(c) 5
(d) 6
(e) none of the above
13.96 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 1, 9, and 17 days, respectively, compute the PERT time for this activity.
(a) 4
(b) 8
(c) 9
(d) 18
(e) none of the above
13.97 Given the following activity’s optimistic, most likely, and pessimistic time estimates 3, 6, and 9 days, respectively, compute the PERT variance for this activity.
(a) 3
(b) 1
(c) 9
(d) 6
(e) none of the above
13.98 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 3, 5, and 13 days, respectively, compute the PERT variance for this activity.
(a) 2.5
(b) 5.4
(c) 8.0
(d) 2.8
(e) none of the above
13.99 Given the following activity’s optimistic, most likely, and pessimistic time estimates of 7, 9, and 15 days, respectively, compute the PERT variance for this activity.
(a) 6.0
(b) 2.7
(c) 8.0
(d) 1.8
(e) none of the above
13.100 The project described by:
Activity Immediate
Predecessor Time
(days)
A – 10
B A 4
C A 6
D B, C 7
E D 5
is best represented by which of the following networks?
13.101 The project described by:
Activity Immediate
Predecessor Time
(days)
A – 10
B A 4
C A 6
D B, C 7
E C 5
has a critical path of length:
(a) 21 days
(b) 14 days
(c) 23 days
(d) 32 days
(e) none of the above
13.102 The project described by
Activity Immediate
Predecessor Time
(days)
A – 6
B A 2
C – 8
D B, C 5
E D 7
has a critical path of length
(a) 15 days
(b) 20 days
(c) 17 days
(d) 18 days
(e) none of the above
The following table provides information for questions 13.103 to 13.108.
Table 13-5
The following represents a project with known activity times. All times are in weeks.
Activity Immediate
Predecessor Time
A – 4
B – 3
C A 2
D B 7
E C, D 4
F B 5
G E, F 4
13.103 Using the data in Table 13-5, what is the minimum possible time required for completing the project?
(a) 8
(b) 12
(c) 18
(d) 10
(e) none of the above
13.104 Using the data in Table 13-5, what is the latest possible time that C may be started without delaying completion of the project?
(a) 0
(b) 4
(c) 8
(d) 10
(e) none of the above
13.105 Using the data in Table 13-5, compute the slack time for activity D.
(a) 0
(b) 5
(c) 3
(d) 6
(e) none of the above
13.106 Using the data in Table 13-5, compute the latest finish time for activity E.
(a) 4
(b) 10
(c) 14
(d) 25
(e) none of the above
13.107 Using the data in Table 13.5, determine the latest time activity A can be started without delaying the project completion.
(a) 4
(b) 3
(c) 8
(d) 6
(e) none of the above
13.108 Using the data in Table 13.5, determine the latest time activity A can be finished and not delay any activity?
(a) 4
(b) 0
(c) 8
(d) 5
(e) none of the above
The following table provides data for questions 13.109 to 13.112.
Table 13-6
All activity times are in weeks.
Activity Immediate
Predecessor Optimistic
Time Most Likely
Time Pessimistic
Time
A – 2 8 14
B – 8 8 8
C A 6 9 18
D B 5 11 17
E C, D 3 3 9
F B 5 6 7
13.109 According to the data in Table 13-6, what is the critical path?
(a) A, C, E
(b) B,F
(c) B, D, E
(d) A, B, C, D, F
(e) none of the above
13.110 According to the data in Table 13-6, what is the minimum expected completion time for the project?
(a) 18
(b) 19
(c) 37
(d) 11
(e) none of the above
13.111 According to Table 13-6, there are six activities in the project. Assume the normal distribution is appropriate to use to determine the probability of finishing by a particular time. If you wished to find the probability of finishing the project in 21 weeks or less, it would be necessary to find the variance and then the standard deviation to be used with the normal distribution. What variance would be used?
(a) 5
(b) 4
(c) 8
(d) 12
(e) none of the above
13.112 According to Table 13-6, there are six activities in the project. Assume the normal distribution is appropriate to use to determine the probability of finishing by a particular time. What is the probability that the project is finished in 20 weeks or less (round to two decimals)?
(a) 0.41
(b) 0.91
(c) 0.13
(d) 0.09
(e) none of the above
13.113 Consider a project that has an expected completion time of 50 weeks and a standard deviation of 9 weeks. What is the probability that the project is finished in 57 weeks or less (round to two decimals)?
(a) 0.68
(b) 0.78
(c) 0.22
(d) 0.32
(e) none of the above
13.114 Your company is considering submitting a bid on a major project. You determine that the expected completion time is 150 weeks and the standard deviation is 10 weeks. It is assumed that the normal distribution applies. You wish to set the due date for the project such that there is a 95 percent chance that the project will be finished by this time. What due date should be set?
(a) 108.0
(b) 160.4
(c) 166.5
(d) 135.0
(e) none of the above
The following table provides information for questions 13.115 to 13.117.
Table 13-7
Activity Immediate
Predecessor Time ES EF LS LF
A – 4 0 4 7 10
B – 5 0 5 0 5
C A 3 4 7 10 13
D B 8 5 13 5 13
E B 2 5 7 16 18
F C, D 3 13 16 15 18
G C, D 7 13 20 13 20
H E, F 2 16 18 18 20
13.115 How long could activity E be delayed without delaying the completion of the project?
(a) 7
(b) 16
(c) 11
(d) 18
(e) none of the above
13.116 How long could activity F be delayed without delaying the project?
(a) 2
(b) 3
(c) 14
(d) 16
(e) none of the above
13.117 What is the minimum possible time required for completing the project?
(a) 14
(b) 20
(c) 17
(d) 20
(e) none of the above
The following table provides information for questions 13.118 to 13.120.
Table 13-8
Activity
Immediate
Predecessor Optimistic
Most
Likely Pessimistic
Average
2
A – 2 3 4 3 0.333 0.111
B – 2 5 8 5 1.000 1.000
C A 1 2 9 3 1.330 1.780
D A 5 5 5 5 0.000 0.000
E B, C 6 7 8 7 0.333 0.111
F B 12 12 12 12 0.000 0.000
G D, E 1 5 9 6 1.333 1.780
H G, F 1 4 8 4 1.167 1.362
13.118 Which activities are part of the critical path?
(a) A, B, E, G, H
(b) A, C, E, G, H
(c) A, D, G, H
(d) B, F, H
(e) none of the above
13.119 What is the variance of the critical path?
(a) 5.222
(b) 4.364
(c) 1.362
(d) 5.144
(e) none of the above
13.120 If the normal distribution were used to find the probability of finishing this project in 24 weeks or less, what mean and variance would be used?
(a) 20 and 5.144
(b) 23 and 5.144
(c) 23 and 5.222
(d) 20 and 4.222
(e) none of the above
*13.121 Which of the following best presents the project defined below?
Activity Predecessor
A –
B –
C A
D B
E D & C
F B
G E
(b)
(e) none of the above
*13.122 Assume a particular activity has an optimistic time of 10 weeks, a most likely time of 12 weeks, and an expected time of 14 weeks. What is its pessimistic time?
(a) 12 weeks
(b) 18 weeks
(c) 26 weeks
(d) 30 weeks
(e) none of the above
*13.123 Assume a particular activity has an expected time of 24 weeks, a pessimistic time of 30 weeks, and a most likely time of 27 weeks. What is the optimistic time?
(a) 10 weeks
(b) 8 weeks
(c) 7 weeks
(d) 12 weeks
(e) none of the above
*13.124 Assume an activity has the following times: optimistic = 10 weeks, most likely = 25 weeks, pessimistic = 40 weeks. What is the expected time?
(a) 10 weeks
(b) 25 weeks
(c) 40 weeks
(d) 30 weeks
(e) none of the above
The following figure (Fig 13.1) is to be used as data for problems 13.129 – 13.135.
*13.125 Given the network in Figure 13.1, the critical path is
(a) A,C,F,H
(b) B,D,E,F,H
(c) A,C,E,G,H
(d) B,D,G,E,F,H
(e) none of the above
*13.126 Given the network in Figure 13.1, the time to complete those activities on the critical path is expected to be
(a) 20
(b) 22
(c) 25
(d) 26
(e) none of the